Suppose that a cyclist began a 510 mi ride across a state at the western edge of the state at the same that a car traveling toward it leaves the eastern end of the state if the bicycle and car met after 8.5 hr and the car traveled 33.4 mph faster than the bicycle find average rate of each

Answer 1

Db + Dc = 510 mi.
Vb*t + Vc*t = 510.
Vb*t + (Vb+33.4)t = 510.
t = 8.5 hrs.
Vb = ?

Vc = Vb + 33.4.