(v1 + v2)7.5 = 450
so
v1 + v2 = 60 miles/hour
and
v1 - v2 = 30.4
------------------ add
2 v1 = 90.4
v1 = 45.2 miles/hour
so
v2 = 14.8 miles/hour
Suppose that a cyclist began a 450 mi ride across a state at the western edge of the state, at the same time that a car traveling toward it leaves the eastern end of the state. If the bicycle and car met after 7.5 hr and the car traveled 30.4 mph faster than the bicycle, find the average rate of each.
1 answer
1 answer