Suppose that a car can accelerate from 30 mph to 50 mph in 4 seconds. Assuming a constant acceleration, find the acceleration (in miles per second squared) of the car and find the distance traveled by the car during the 4 seconds.

Answer 1

30 mph = 30/3600 miles/sec = 1/120 mps
50 mph = 1/72 mps

v = at + c
when t = 0, v = 1/120, so c = 1/120

v = at + 1/120
when t = 4, v = 1/72
1/72 = 4a + 1/120
4a = 1/180

a = 1/720 miles/sec^2

v = (1/720)t + 1/120
if the distance is s

s = (1/1440)t^2 + (1/120)t + k
when t = 0, s = 0, ---> k=0

s = (1/1440)t^2 + (1/120)t
when t = 4
s = (1/1440)(16) + (1/120)(4) = 2/45 miles

Answer 2

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Answer 3

*passive agressive attitude intensifies*