suppose that a 70.0kg box is pulled by a 400.N force at an angle of 30 degrees to the horizontal. the coefficient of sliding friction is 0.500. what is the acceleration of the box?

Answer 1

the horizontal force is 400cos30
vertical force=400Sin30

net apparent weight=70g-400sin30

acceleration=nethorizonalforce/mass

= (400cos30-mu(70g-400sin30)/70