Suppose P(C|D) =0.59, P(D) =0.44, and P (D|C) =0.38. What is P(C) rounded to two decimal places? A) 0.42 b) 0.57 c) 0.68 d) 0.34?

Answer 1

since
P(C|D) = P(C∩D)/P(D)
P(D|C) = P(C∩D)/P(C)

P(C∩D) = P(C|D)*P(D) = P(D|C)*P(C)

Now just plug in your numbers