Suppose an astronaut drops a feather from 1.6 m above the surface of the Moon. If the acceleration due to gravity on the Moon is 1.62 m/s2 downward, how long does it take the feather to hit the Moon's surface?

Answer 1

h = 0.5*g*t^2 = 1.8.
0.5*1.62*t^2 = 1.8,
t =