well, using your trajectory equation
y = tanθ x - g/(2 (v cosθ)^2) x^2
just plug in your numbers and solve for v:
0.9657x - 9.4795/v^2 x^2 = 2.4
and if x=31, you have
v = 18.19 m/s
Suppose a soccer player kicks the ball from a distance 31 m toward the goal. Find the initial speed of the ball if it just passes over the goal, 2.4 m above the ground, given the initial direction to be 44° above the horizontal.
Help please !
1 answer
1 answer