Asked by Lee

Suppose a parabola has a vertex (-4,7) and also passes through the point (-3,8) Write the equation of the parabola in vertex form.
f(x)=a(x-h)^2+k
I believe h=-4
k=7
Not sure what to do from here.
Answered by Steve
from the vertex, you know that

y = a(x+4)^2 + 7

Now just plug in (-3,8) to find a:

8 = a(1)+7
1 = a

y = (x+4)^2 + 7
Answered by Lee
I'm not sure what your saying
Answered by Steve
you seemed to be able to figure out h and k for the vertex, so what's the hangup? All I did was use your equation and use the values x=-3 and y=8 to solve for a.
Answered by Lee
y=a(x-h)^2+k
y=a(x+4)^2+7
8=a((x-3)+4)^2+7
8=a(1)^2+7
1=a
4=(x+4)^2+7
Is this right?
Answered by Steve
well, I'd say yes, since it agrees with the equation I posted above. (sort of; not sure what the 4 means)
Answered by Lee
sorry was y we have to show our steps when figuring problems thank you
Answered by Senator Armstrong
Nanomachines Son! You can't hurt me Jack!
There are no AI answers yet. The ability to request AI answers is coming soon!