1104/138 = 8 half-lives
after 8 half-lives, 1/256 remains, or 0.148g
Suppose a laboratory has a 38 g sample of polonium-210. The half-life of polonium-210 is about 138 days. How many half-lives of polonium-210 occur in 1104 days? How much polonium is in the sample 1104 days later?
6 answers
How many half-lives of polonium-210 occur in 1104 days? 1104/138 = 8.0 half-lives
How much polonium is in the sample 1104 days later? 38 g * (1/2)^8 = 0.148 g
How much polonium is in the sample 1104 days later? 38 g * (1/2)^8 = 0.148 g
Thank you both very much.
8; 2,622 g
8; 0.11
8';0.148