Suppose a galvanic cell contains one nickel electrode and one copper electrode. At 25°C, nickel has a negative reduction potential and copper has a positive reduction potential. At which electrode will reduction occur?

Question

- I believe copper will be oxidised and nickel reduced, correct?

Can someone also explain what happens in the galvanic cell.

Thank you

Answer 1

Cu^2+ + 2e ==> Cu Eo = +0.34
Ni^2+ + 2e ==> Ni Eo = -0.25

To make a spontaneous cell we must have a positive cell potential; therefore,
Ni ==> Ni^2+ + 2e E = +0.25
Cu^2+ + 2e ==> Cu E = +0.34
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Ni + Cu^2+ ==> Ni^2+ + Cu Ecell = +0.59
Oxidation is the loss of electrons; which loses electrons.