Use Nernst.
0.61=0.79-(0.0592/2)*log 0.20/x
-0.18=-0.296*log 0.20/x
6.0810811=log 0.20/x
1205260.93387=0.20/x
x=1.6593917083*10^-7
A galvanic cell has an iron electrode in contact with 0.20 M FeSO4 and a copper electrode in contact with a CuSO4 solution. If the measured cell potential at 25 degrees Celcius is 0.61 V , what is the concentration of Cu2+ in the CuSO4 solution?
1 answer