Suppose a car's motor draws 231 Ampere of current for 6.3 sec to start the car. What mass of Pb is oxidized in the lead-acid battery to supply this much electricity?

Answer 1

231 A x 6.3 sec = about 1,500 Coulombs but you need to do it more accurately.
96,485 coulombs will oxidize 1/2 mol Pb which is 207.2/2 = 103.6 g Pb. The amount of Pb deposited will be

103.6 x (1,500/95,485) = ? g Pb.

Answer 2

Thanks!