Three similar ideal cells (no internal resistances) supply current of 0.5 Ampere to a 10 Ohms resistor when they are in the parallel.How much current will they supply to the same risistor when they are connected in series aiding?

Answer 1

E=I*R = 0.5 * 10=5 Volts, each battery.

I = E/R = 15/10 = 1.5 Amps.