If the events are independent, the probability of both/all events occurring is determined by multiplying the probabilities of the individual events.
(1-.90)^3 = ?
Suppose a basketball player is an excellent free throw shooter and makes 90% of his free throws (i.e., he has a 90% chance of making a single free throw). Assume that free throw shots are independent of one another. Suppose this player gets to shoot three free throws. Find the probability that he misses all three consecutive free throws.
3 answers
.271
.10*.10*.10=.001
2 answers