Suppose a baseball player had 211 hits in a season. In the given probability distribution, the random variable X represents the number of hits the player obtained in the game.

Question

x P(x)
0 0.1879
1 0.4106
2 0.2157
3 0.1174
4 0.0624
5 0.0060
a.) Compute and interpret the mean of the random variable X
b.) Compute the standard deviation of the random variable X.

Answer 1

To calculate the mean we add up all of the numbers and divide by the total number amount for e.g. you have 5 numbers here. Add them up and divide by 5

b) The standard deviation is that complicating equation. You can check this on google to get the exact formula and i think if you type in standard deviation calculator you can plug in the numbers on the website and check this with your answer

Answer 2

µ= x * p(x)
= 0(0.11879) + 1( 0.4106) + 2(0.2157) + 3(0.1174) + 4 (0.0624) + 5(0.0060) = ?

σ^2 = x^2 * p(x)
= 0^2(0.11879) + 1^2(0.4106) + 2^2(0.2157) + 3^2(0.1174) + 4^2(0.0624) + 5^2(0.0060) = ?

sd = sqrt( σ^2- (µ^2))

Answer 3

Suppose a baseball player had 212 hits in a season. In given probability distribution, the random variable X represents the number of the player obtained in a game
0 0.0908
1 0.4677
2 0.2988
3 0.1163
4 0.0147
5 0.0117