Suppose a 65-kg boy and a 45-kg girl use a massless rope in a tug-of-war on an icy, resistance-free surface. If the acceleration of the girl toward the boy is 3.0 m/s2, find the magnitude of the acceleration of the boy toward the girl.

Answer 1

The forces are the same
massman*a_man=massgirl*a_girl

solve for the man's acceleration

Answer 2

Tension of rope = T N
Mass of girl, m = 45 kg
Acceleration = 3.0 m/s²
T = ma = 135 N
Mass of boy, M = 65 kg
T = MA,
solve for acceleration A.

Answer 3

girl: 135 N
boy mass: 65 kg

135/65 = 2.0769 =

2.077 m/s^2

Answer 4

135 Newtons and 2.077 m/s2

no pb m8

Answer 5

um lol but who wants to know these answers?

Answer 6

i want to know them

Answer 7

i want to know them too

Answer 8

-2.1

Answer 9

Mass of the boy is
m
1
=
65

k
g

Mass of the girl is
m
2
=
45

k
g

Acceleration of the girl towards the boy is:

a
1
=
3

m
/
s
2

For the force applied by the boy on the girl :

F
1
=
m
2
×
a
1
F
1
=
45
×
3
F
1
=
135

N
Now since the action and reaction pair will be same (
F
1
=
F
2
)now for the acceleration of the girl:

a
2
=
F
2
m
1
a
2
=
135
65
a
2
=
2.07

m
/
s
2
Thus, the acceleration of the girl towards the boy is
2.07

m
/
s
2