Suppose a 63-kg boy and a 44-kg girl use a massless rope in a tug-of-war on an icy, resistance-free surface. If the acceleration of the girl toward the boy is 3.0 m/s2, find the magnitude of the acceleration of the boy toward the girl.

Answer 1

The magnitude of the acceleration of the boy toward the girl is 4.5 m/s2.

This can be calculated using Newton's Second Law of Motion:

F = ma

F = (63 kg)(3.0 m/s2) - (44 kg)(a)

a = 4.5 m/s2

Answer 2

Close, just switch some numbers around.