Suppose 25 children who weigh the same are playing a game of tug-of-war. Five children pull with 10 newtons of force, while ten children pull with 15 newtons of force in the opposite direction. How can one determine the net force on the rope

Question

options:

The forces are in the same direction, so the newtons can be added.
The forces are in the same direction, so the newtons can be added.

The forces are in opposite directions, so the newtons can be divided.
The forces are in opposite directions, so the newtons can be divided.

The newtons are in the same direction, so the newtons can be multiplied.
The newtons are in the same direction, so the newtons can be multiplied.

The forces are in opposite directions, so the newtons can be subtracted.

Answer 1

To determine the net force on the rope in a tug-of-war scenario, you need to consider the forces acting in opposite directions.

In this case:

• Five children pull with a force of 10 newtons each: \(5 \times 10 , \text{N} = 50 , \text{N}\)
• Ten children pull with a force of 15 newtons each: \(10 \times 15 , \text{N} = 150 , \text{N}\)

Since these forces are in opposite directions, you subtract the smaller force from the larger force to get the net force.

Net force = Force in one direction - Force in the opposite direction Net force = \(150 , \text{N} - 50 , \text{N} = 100 , \text{N}\) (in the direction of the heavier pull).

So the correct answer is:

The forces are in opposite directions, so the newtons can be subtracted.

Answer 2

An object at rest remains at rest. An object in motion remains in motion unless acted upon by an outside force. This describes which of Newton’s Laws of Motion?

options:

Second and Third Laws of Motion
Second and Third Laws of Motion

First Law of Motion
First Law of Motion

First and Third Laws of Motion
First and Third Laws of Motion

Second Law of Motion

Answer 3

The statement "An object at rest remains at rest. An object in motion remains in motion unless acted upon by an outside force" describes Newton's First Law of Motion.

This law is often referred to as the law of inertia. It states that an object will not change its state of motion (whether at rest or moving) unless acted upon by an external force.

Thus, the correct answer is:

First Law of Motion.

Answer 4

Two forces act on an object. One force has a magnitude of 10 N directed north, and the other force has a magnitude of 2 N directed south. What is the net force on the object?

options:

12 N south
12 N south

25 N north
25 N north

8 N north
8 N north

8 N south

Answer 5

To find the net force on the object, you need to combine the two forces while considering their directions.

1. The first force is 10 N directed north.
2. The second force is 2 N directed south.

Since the forces are in opposite directions, you subtract the smaller force from the larger force:

Net force = Force (north) - Force (south) Net force = \(10 , \text{N} - 2 , \text{N} = 8 , \text{N}\)

Since the greater force (10 N) is directed north, the net force will also be directed north.

Therefore, the net force on the object is:

8 N north.

Answer 6

While playing her soccer game, Samantha runs down the field at 10 meters per second. She has a constant speed and does not change direction. What is Samantha’s acceleration

option:

The acceleration is 10 m/s^2 because her velocity increased.
The acceleration is 10 m/s^2 because her velocity increased.

The acceleration is 0 m/s^2 because her velocity increased.
The acceleration is 0 m/s^2 because her velocity increased.

The acceleration is 0 m/s^2 because her velocity did not change.
The acceleration is 0 m/s^2 because her velocity did not change.

The acceleration is 10 m/s^2 because her velocity did not chang

Answer 7

Acceleration is defined as the rate of change of velocity with respect to time. If an object is moving with a constant speed and does not change direction, its velocity is not changing.

In Samantha's case:

• She runs down the field at a constant speed of 10 meters per second.
• Since her speed and direction remain constant, there is no change in her velocity.

Therefore, her acceleration is:

The acceleration is 0 m/s² because her velocity did not change.