Question

Suppose 25 children who weigh the same are playing a game of tug-of-war. Five children pull with 10 newtons of force, while ten children pull with 15 newtons of force in the opposite direction. How can one determine the net force on the rope?(1 point) Responses The forces are in opposite directions, so the newtons can be subtracted. The forces are in opposite directions, so the newtons can be subtracted. The newtons are in the same direction, so the newtons can be multiplied. The newtons are in the same direction, so the newtons can be multiplied. The forces are in opposite directions, so the newtons can be divided. The forces are in opposite directions, so the newtons can be divided. The forces are in the same direction, so the newtons can be added.

Answer 1

To determine the net force on the rope in this tug-of-war scenario, we need to consider the forces acting in opposite directions. Here, we have two groups of children pulling with different forces:

• Five children pull with 10 newtons of force each, which totals:
  \( 5 \text{ children} \times 10 \text{ N} = 50 \text{ N} \) in one direction.

• Ten children pull with 15 newtons of force each, which totals:
  \( 10 \text{ children} \times 15 \text{ N} = 150 \text{ N} \) in the opposite direction.

Since the forces are in opposite directions, we will subtract the smaller force from the larger force to find the net force.

Net Force = \( 150 \text{ N} - 50 \text{ N} = 100 \text{ N} \)

Therefore, the correct response is:

The forces are in opposite directions, so the newtons can be subtracted.