What level of significance are you using for your estimate? If P = .05:
95% = mean ± 1.645 SEm
SEm = SD/√n
Suppose 100 randomly selected customers were asked to rate a particular service they recently had on a scale of 0 to 10. The sample mean rating was found to be 7.3. (Assume the population standard deviation of all ratings in the population of customers is 0.8.) Using all this information, estimate the average rating of this service for all customers.
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