Supply the missing quantum number or sub level name.

Question

n. l. ml. name
(a). ? ? 0. 4p
(b). 2. 1. 0. ?
(c). 3. 2. -2. ?
(d). ? ? ? 2s
(e). 3. ? -1. 3p?

Answer 1

I'm not sure, sorry.

Answer 2

This is difficult to do on the internet because of the spacing for html. I'll try to draw n = 1 and n = 2. You follow that and draw n = 3 and n = 4. I won't draw in the s. It is understood there may be 2.

n......1|...........2.........|
l.......0|...0| .....1........|
m.....0|...0| -1...0...+1|
s...............................|

Look at b. That is n = 2, l = 1 and ml = 0. Follow the table. Look at n = 2, beloe that is l = 1 amd m = 0. Since l = 1 that must be a p electron and n = 2 so 2p.
Look at d. It is a 2s electron. That tells you n = 2, s tells you l = 0. If l = 0 then mjl must be 0 also. The rest of them are done the same way.

Answer 3

Supply the missing quantum number or sub level name.
n. l. ml. name
(a). ? ? 0. 4p (4, 1, 0)
(b). 2. 1. 0. ? ()
(c). 3. 2. -2. ?
(d). ? ? ? 2s2s
(e). 3. ? -1. 3p?

n => 1, 2, 3, 4, …
l => s, p, d, f, g, h … => 0, 1, 2, 3, 4, 5, 6, …
m =>.......... - 3 -2 -1 0 +1 +2 +3
…………………….…….......…s
……………...…….…......p₋₁....p₀....p₊₁
………………........d₋₂.....d₋₁....d₀....d₊₁....d₊₂
…………........f₋₃....f₋₂......f₋₁.....f₀.....f₊₁.....f₊₂.....f₊₃

a. (?, ?, 0) => 4p => (4, 1, 0)
b. (2, 1, 0) => 2p₀
c. (3, 2, -2) => 3d₋₂
d. (?, ?, ?) => 2s => (2, 0, 0)
e. (3, ?, -1) => 3p => (3, 1, -1)