Asked by Katie

Sulfuric acid dissolves aluminum metal according to the following reaction:

2Al(s)+3H2SO4(aq)→Al2(SO4)3(aq)+3H2(g)

Suppose you wanted to dissolve an aluminum block with a mass of 14.5g .

1.) What minimum mass of H2SO4 would you need?

2.)What mass of H2 gas would be produced by the complete reaction of the aluminum block?


Please help, I am confused on where to even start
Answered by bobpursley
a. how many moles is 14.5g Al? Figure that.
Then you need 3/2 of those moles of H2SO4. Convert to grams...


b. Moles of gas=3/2 moles of aluminum. Convert to grams H2
Answered by Anonymous
1.= 80.7
Answered by Anonymous
What mass of H2 gas would be produced by the complete raction of the aluminum block
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