Sulfuric acid dissolves aluminum metal according to the following reaction:

Question

2Al(s)+3H2SO4(aq)→Al2(SO4)3(aq)+3H2(g)

Suppose you wanted to dissolve an aluminum block with a mass of 14.5g .

1.) What minimum mass of H2SO4 would you need?

2.)What mass of H2 gas would be produced by the complete reaction of the aluminum block?

Please help, I am confused on where to even start

Answer 1

a. how many moles is 14.5g Al? Figure that.
Then you need 3/2 of those moles of H2SO4. Convert to grams...

b. Moles of gas=3/2 moles of aluminum. Convert to grams H2

Answer 2

1.= 80.7

Answer 3

What mass of H2 gas would be produced by the complete raction of the aluminum block