Subtract 3r from both sides of the equation to get rid of the 3r on the left, so that all the r terms are on the right side of the equation.

4
1

(12r−8)
=
6r+10

3r − 2
=
6r + 10

3r

3r

=

1 answer

To subtract \(3r\) from both sides of the equation \(3r - 2 = 6r + 10\), we perform the following steps:

  1. Start with the original equation: \[ 3r - 2 = 6r + 10 \]

  2. Subtract \(3r\) from both sides: \[ 3r - 3r - 2 = 6r - 3r + 10 \]

  3. Simplify both sides: \[ -2 = 3r + 10 \]

Now, all the \(r\) terms are on the right side of the equation. The equation is now: \[ -2 = 3r + 10 \]