The frequency of the second class is 6.
Since the class width is 6 and the lower limit of the first class is 50, this means the first class goes from 50-55. This would put the second class at 56-61. There are 6 data points in this set that would go in the second class.
I can send a link telling you a more specific way to do this if you would like?
Students heights in inches were obtained as part of a study and a frequency distribution was constructed with the first class having a lower limit of 50 inches. The class widths are 6 inches. What is the frequency of the second class in the distribution?
51 51 54 56 56 57 59 61 61 62 65 69 70 70 71 71 72 73
a. 10
b. 6
c. 4
d. 5
I'm not sure how to do this problem, could someone explain? I can give my own guess if you want but I would like to know how to do it first...
3 answers
class A 50 to 56 five members
class B 57 to 63 five members
class C 64 to 70 four members
class D 70 to 76 six members
looks like A and B are tied for second at five
class B 57 to 63 five members
class C 64 to 70 four members
class D 70 to 76 six members
looks like A and B are tied for second at five
Thank you I understand now, I can figure the rest out on my own.