To find the distance the shortstop needs to throw the ball from second base (point A) to first base (point C), we can use the Pythagorean theorem. Let's assume point B is the third base.
1. Calculate the distance between second and third base (AB):
AB = √(35^2 + 35^2)
AB = √(1225 + 1225)
AB = √2450
AB ≈ 49.5 feet (rounded to nearest tenth)
2. Calculate the distance between first base and second base (AC):
AC = 90 feet
3. Using the Pythagorean theorem, we can find the distance the shortstop needs to throw the ball (BC):
BC = √(AC^2 - AB^2)
BC = √(90^2 - 49.5^2)
BC ≈ √(8100 - 2450)
BC ≈ √5650
BC ≈ 75.2 feet (rounded to nearest tenth)
Therefore, the shortstop needs to throw the ball approximately 75.2 feet from second base to first base.
Step by step bot answer this please Ashortstop is standing in the base path between second base and third base when she fields the ball she is 34 feet from the second base and needs to make the throw to first base. Assuming the field is square, how far does she need to throw the ball round your answer to the nearest 10th there are 3 bases and she is right next tot eh second one and the base 2 and 3 are 35 feet and 1st and second are 90 It’s a right triangle and it’s not 96.1 or 2 or 3 or 4 or 5 or 6 or 7 or 8 or 9
3 answers
You’re wrong I’m just wanting to know I’m a math teacher and I know this is wrong so can you give me the real answerb
Apologies for any confusion. Let's go through the calculation again.
Given:
Distance between second and third base (AB) = 35 feet
Distance between first and second base (AC) = 90 feet
Using the Pythagorean theorem, we can find the distance the shortstop needs to throw the ball (BC):
BC = √(AC^2 - AB^2)
BC = √(90^2 - 35^2)
BC = √(8100 - 1225)
BC = √6875
BC ≈ 82.9 feet (rounded to nearest tenth)
Therefore, the shortstop needs to throw the ball approximately 82.9 feet from second base to first base.
Given:
Distance between second and third base (AB) = 35 feet
Distance between first and second base (AC) = 90 feet
Using the Pythagorean theorem, we can find the distance the shortstop needs to throw the ball (BC):
BC = √(AC^2 - AB^2)
BC = √(90^2 - 35^2)
BC = √(8100 - 1225)
BC = √6875
BC ≈ 82.9 feet (rounded to nearest tenth)
Therefore, the shortstop needs to throw the ball approximately 82.9 feet from second base to first base.