To find the distance the shortstop needs to throw the ball, we can use the Pythagorean theorem.
1. First, let's label the distances:
- Distance from the shortstop to second base (A) = 35 feet
- Distance from second base to first base (B) = 90 feet (given)
- Distance the shortstop needs to throw (C) = ?
2. Now, let's use the Pythagorean theorem:
C² = A² + B²
Plugging in the values:
C² = 35² + 90²
3. Calculate:
C² = 1225 + 8100
C² = 9325
4. Take the square root of both sides to find C:
√C² = √9325
C ≈ 96.42 (rounded to the nearest 10th)
Therefore, the shortstop needs to throw the ball approximately 96.4 feet (rounded to the nearest 10th).
Step by step bot answer this please A shortstop is standing in the base path between second base and third base when she fields the ball she is 35 feet from the second base and needs to make the throw to first base. Assuming the field is square, how far does she need to throw the ball round your answer to the nearest 10th there are 3 bases and she is right next tot eh second one and the base 2 and 3 are 35 feet and 1st and second are 90 It’s a right triangle and it’s not 96
3 answers
Step by step bot answer this please A shortstop is standing in the base path between second base and third base when she fields the ball she is 35 feet from the second base and needs to make the throw to first base. Assuming the field is square, how far does she need to throw the ball round your answer to the nearest 10th there are 3 bases and she is right next tot eh second one and the base 2 and 3 are 35 feet and 1st and second are 90 It’s a right triangle and it’s not 96.1 or 2 or 3 or 4 or 5 or 6 or 7 or 8 or 9
Apologies for the previous incorrect response. Let's solve the problem correctly.
1. When the shortstop fields the ball, she is 35 feet away from second base.
2. The distance between second base and first base is given as 90 feet.
3. Since the field is square, we can form a right triangle with the shortstop as the right angle vertex, the 35-foot distance being the vertical side (adjacent side), and the 90-foot distance being the horizontal side (opposite side).
4. To find the length of the hypotenuse (the distance the shortstop needs to throw the ball), we can use the Pythagorean theorem: c² = a² + b², where c is the length of the hypotenuse and a and b are the lengths of the other two sides.
5. Plugging in the values:
c² = 35² + 90²
c² = 1225 + 8100
c² = 9325
6. Taking the square root of both sides to find c:
c ≈ √9325
c ≈ 96.4 (rounded to the nearest 10th)
Therefore, the shortstop needs to throw the ball approximately 96.4 feet (rounded to the nearest 10th) to reach first base.
1. When the shortstop fields the ball, she is 35 feet away from second base.
2. The distance between second base and first base is given as 90 feet.
3. Since the field is square, we can form a right triangle with the shortstop as the right angle vertex, the 35-foot distance being the vertical side (adjacent side), and the 90-foot distance being the horizontal side (opposite side).
4. To find the length of the hypotenuse (the distance the shortstop needs to throw the ball), we can use the Pythagorean theorem: c² = a² + b², where c is the length of the hypotenuse and a and b are the lengths of the other two sides.
5. Plugging in the values:
c² = 35² + 90²
c² = 1225 + 8100
c² = 9325
6. Taking the square root of both sides to find c:
c ≈ √9325
c ≈ 96.4 (rounded to the nearest 10th)
Therefore, the shortstop needs to throw the ball approximately 96.4 feet (rounded to the nearest 10th) to reach first base.
1 answer