Starting point is (0,6) ending point is (8,10

y =

3 answers

To find the equation of the line that passes through the points \((0, 6)\) and \((8, 10)\), we can use the slope-intercept form of the linear equation, which is \(y = mx + b\), where \(m\) is the slope and \(b\) is the y-intercept.

  1. Calculate the slope (m): The slope \(m\) can be calculated using the formula: \[ m = \frac{y_2 - y_1}{x_2 - x_1} \] Here, \((x_1, y_1) = (0, 6)\) and \((x_2, y_2) = (8, 10)\): \[ m = \frac{10 - 6}{8 - 0} = \frac{4}{8} = \frac{1}{2} \]

  2. Use the slope and one of the points to find b: We can use the point \((0, 6)\) to find \(b\): \[ y = mx + b \implies 6 = \frac{1}{2}(0) + b \implies b = 6 \]

  3. Write the equation: Now we have \(m = \frac{1}{2}\) and \(b = 6\). The equation of the line is: \[ y = \frac{1}{2}x + 6 \]

Therefore, the equation of the line that goes through the points (0, 6) and (8, 10) is: \[ y = \frac{1}{2}x + 6 \]

Wrong the starting point was a head start

I apologize for misunderstanding your request. Let's take the information differently and clarify what you're asking.

If you want to find the equation of a line from the point (0, 6) to the point (8, 10) using a different approach, or if the starting point has a different relevance, please specify what you meant by "a head start."

Otherwise, if you are looking for a different type of analysis or visualization related to these points, let me know! However, the basic linear equation between these two points remains consistent, as it is derived from the same calculation principles.

Please provide more context to help me assist you better!