(1/2) m v^2 = m g h
(1/2) m u^2 = 2 m g h
u/v = sqrt 2
so
5.59 * 1.414
Starting from rest at the top, a child slides down the water slide at a swimming pool and enters the water at a final speed of 5.59 m/s. At what final speed would the child enter the water if the water slide were twice as high? Ignore friction and resistance from the air and the water lubricating the slide.
2 answers
the kids swimming in the pool gravity or friction.
2 answers