Starting from rest, a car accelerates at 2.5 m/s^2 up a hill that is inclined 5.4 ^\circ above the horizontal.

Question

Starting from rest, a car accelerates at 2.5 m/s^2 up a hill that is inclined 5.4  ^\circ above the horizontal. 
how far the car travel horizontally in 15s?

Henry · Answer

I'm assuming the angle of inclination is 5.4 deg. a(h) = 2.5m/s^2 * cos5.4 = 2.49m/s^2 = hor. component of acceleration. d = Vo*t + 0.5at^2, d = 0 + 0.5*2.49*(15)^2 = 280m.