friction force up slope on sled
= 0.20 * m* g * cos 25
So
T = m g sin 25 - 0.20 m g cos 25
= m g (sin 25 - 0.20 cos 25)
A sled of mass 30 kg is at rest on a hill that is inclined at 25° to the horizontal; the coefficient of friction between the hill and the sled is 0.20 and the sled is held at rest by a rope attached to a post to keep it from sliding down the hill (the rope is parallel to the hillside). Calculate the magnitude of the tension in the rope.
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By the way your diagrams do not show up here. Copy and paste does not work on this site (for obvious reasons).
thank you!!!
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