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Start by finding the value of x. Solve on paper, then enter your answers on Zearn.

y= 5x+6
x= 23−2y
x =

y = ?

1 answer

To solve the system of equations given:

  1. \( y = 5x + 6 \) (Equation 1)
  2. \( x = 23 - 2y \) (Equation 2)

We can start by substituting Equation 1 into Equation 2.

  1. From Equation 1, we have \( y = 5x + 6 \).
  2. Substitute this expression for \( y \) into Equation 2:

\[ x = 23 - 2(5x + 6) \]

Now, simplify the equation:

\[ x = 23 - 10x - 12 \]

Combine like terms:

\[ x = 11 - 10x \]

Next, add \( 10x \) to both sides:

\[ x + 10x = 11 \]

This simplifies to:

\[ 11x = 11 \]

Now divide both sides by 11:

\[ x = 1 \]

Now that we have the value of \( x \), we can substitute it back into Equation 1 to find \( y \):

\[ y = 5(1) + 6 \] \[ y = 5 + 6 = 11 \]

So, the values are:

\[ x = 1 \] \[ y = 11 \]

Feel free to enter these values into Zearn!