huh? what's to start?
The 1st equation is the solution to the second. All you have to do is find C such that
y(x^2+y) = C
goes through (0,2).
2(0+2) = C
Some of the curves corresponding to different values of C in the general solution of the differential equation are shown in the graph. Find the particular solution that passes through the point (0, 2).
y(x^2+y) = C
2xy + (x^2+2y)y' = 0
How would I start this problem to solve for the solution? Thanks in advance!
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