Some how TRAIN A travelling at 36 m/s, is accidentally sidetracked onto the train track for TRAIN A. The TRAIN A engineer spots TRAIN A 100 m ahead on the same track and travelling in the same direction. The engineer jams on the brakes and slows TRAIN B at a rate of 3m/s^2. TRAIN A's conductor was unaware of the situation. If the speed of the local train is 11 m/s will the express be able to stop in time or will there be a collision?

Question

Some how TRAIN A travelling at 36 m/s, is accidentally sidetracked onto the train track for TRAIN A. The TRAIN A engineer spots TRAIN A 100 m ahead on the same track and travelling in the same direction. The engineer jams on the brakes and slows TRAIN B at a rate of 3m/s^2. TRAIN A's conductor was unaware of the situation. If the speed of the local train is 11 m/s will the express be able to stop in time or will there be a collision? 
Support you answer with a calculation.

Please help me solve this ASAP, thank you.

Taylor · Answer

Sorry Train A is sidetracked onto Train B's train track, which is 100 m ahead of Train A

hh · Answer

v=0 u=36m/s a=3m/s^2 t=? v=u+at 0=36m/s-3m/s^2t 0=-36=3t t=36/2 =18 seconds.

jay · Answer

the answer is 12 seconds. you divide 36 by 3 not 2.