i forgot put the other one
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-(x+4) = -(x-2)
-x+4 = -x+2
4 = 2 no solution
solving equations with two absolute value brackets
|x+4| = |x-2|
so i want to know how to do this? do i always have to write out the four piecewise possibilities? that be ++ -+ and +-
++
x+4 = x-2
4 = -2 not solution
-+
-(x+4) = x-2
-x-4 = x-2
-4 = 2x-2
-1 = x solution
+-
x+4 = -(x-2)
x+4 = -x+2
2x+4 = 2
x = -1 solution
2 answers
you are correct.