Asked by Leah
Find all solutions (answers should be given in simplified form). Some answers may involve the number i.
*I will use lowercase l to represent absolute value lines.*
3 lx-1l + 4 = 19
We've never really worked with absolute value in solving equations before. Do I distribute the 3 to the x-1 as normal, or do something different?
This is my first idea:
3 lx-1l = 15
lx-1l = 5
x = -4, 6
*I will use lowercase l to represent absolute value lines.*
3 lx-1l + 4 = 19
We've never really worked with absolute value in solving equations before. Do I distribute the 3 to the x-1 as normal, or do something different?
This is my first idea:
3 lx-1l = 15
lx-1l = 5
x = -4, 6
Answers
Answered by
MathMate
No, you do not distribute the absolute value signs.
What you did is correct, i.e. keep the absolute value quantity intact, and eventually evaluate the value as either positive or negative.
|x-1|=5 means
x-1=5 => x=5+1=6
or
-(x-1)=5 => x=1-5=-4
What you did is correct, i.e. keep the absolute value quantity intact, and eventually evaluate the value as either positive or negative.
|x-1|=5 means
x-1=5 => x=5+1=6
or
-(x-1)=5 => x=1-5=-4
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