To solve the equation \( x^2 = \frac{16}{25} \) by inspection, we need to identify the values of \( x \) that will satisfy the equation.
First, we take the square root of both sides:
\[ x = \pm \sqrt{\frac{16}{25}} \]
Calculating the square root, we find:
\[ \sqrt{\frac{16}{25}} = \frac{\sqrt{16}}{\sqrt{25}} = \frac{4}{5} \]
Thus, the solutions for \( x \) are:
\[ x = \frac{4}{5} \quad \text{and} \quad x = -\frac{4}{5} \]
Now, we need to list the two real solutions in order, with the lesser number first. Therefore, the solutions are:
\[ -\frac{4}{5}, \frac{4}{5} \]
In simplest fraction form, the answer is:
\[ -\frac{4}{5}, \frac{4}{5} \]
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