To solve the equation \( x^2 = \frac{16}{25} \) by inspection, we are looking for values of \( x \) such that when squared, they equal \( \frac{16}{25} \).
We can take the square root of both sides:
\[ x = \pm \sqrt{\frac{16}{25}} \]
Calculating the square root gives us:
\[ \sqrt{\frac{16}{25}} = \frac{\sqrt{16}}{\sqrt{25}} = \frac{4}{5} \]
Thus, the two solutions are:
\[ x = \frac{4}{5} \quad \text{and} \quad x = -\frac{4}{5} \]
To list the solutions from least to greatest, we write:
\[ -\frac{4}{5}, \quad \frac{4}{5} \]
So the final answer is:
\[ -\frac{4}{5}, \frac{4}{5} \]
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