To solve the equation \( x^2 = \frac{16}{25} \) by inspection, we need to find values of \( x \) that satisfy the equation.
Taking the square root of both sides, we have:
\[ x = \pm \sqrt{\frac{16}{25}} \]
Calculating the square root, we find:
\[ \sqrt{\frac{16}{25}} = \frac{\sqrt{16}}{\sqrt{25}} = \frac{4}{5} \]
Thus, the two solutions are:
\[ x = \frac{4}{5} \quad \text{and} \quad x = -\frac{4}{5} \]
Since we want to list the lesser number first, the solutions in simplest fraction form are:
\[ -\frac{4}{5}, \frac{4}{5} \]
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