Solve. x=6y-3 2x+7y=13

To solve this system of equations, we will use the method of substitution.

First, solve the first equation for x:
x = 6y - 3

Now, substitute this value of x into the second equation:
2(6y - 3) + 7y = 13

Distribute the 2:
12y - 6 + 7y = 13

Combine like terms:
19y - 6 = 13

Add 6 to both sides:
19y = 19

Divide both sides by 19:
y = 1

Now substitute this value of y back into the first equation to solve for x:
x = 6(1) - 3
x = 6 - 3
x = 3

So the solution to the system of equations is x = 3 and y = 1.

it was wrong

Apologies for the confusion. Let's solve the system of equations again using the method of elimination.

Given equations:
1) x = 6y - 3
2) 2x + 7y = 13

Step 1: Rearrange equation 1) to solve for x:
x = 6y - 3

Step 2: Substitute the value of x from equation 1) into equation 2):
2(6y - 3) + 7y = 13
12y - 6 + 7y = 13
19y - 6 = 13

Step 3: Move the constant terms to one side of the equation:
19y = 13 + 6
19y = 19

Step 4: Solve for y:
y = 19/19
y = 1

Step 5: Substitute the value of y into equation 1) to solve for x:
x = 6(1) - 3
x = 6 - 3
x = 3

The solution to the system of equations is x = 3 and y = 1.