no, I don't think you are using the quadratic formula correctly.
Do you have
for ax^2 + bx + c=0
x = (-b ±√(b^2 - 4ac)/(2a) ??
then for yours
x = (-3 ±√(9-4(1)(3))/2
= (-3 ±√-3)/2 which is a complex number
Solve
x^2 + 3x + 3 = 0
-1 +- sq.rt 1-4 (1)(3)
-1 +- sq.rt 1-12 =
-1 +- i sq.rt 11/2
Is this correct?
4 answers
yes i have that formula
i thought i was told to just put in the numbers for the variables
i thought i was told to just put in the numbers for the variables
but you did not put them in the right way.
ok thanks for your help
1 answer