Solve x^2=36 by inspection. There are two real solutions. Enter the lesser number first.

Answer 1

To solve the equation \( x^2 = 36 \) by inspection, we need to find the numbers \( x \) such that when squared, they equal 36.

The square roots of 36 are:

\[ x = 6 \quad \text{and} \quad x = -6 \]

Thus, the two real solutions are \( -6 \) and \( 6 \).

Entering the lesser number first, the solutions are:

\[ -6, 6 \]

Answer 2

Solve x^2=16/25 by inspection. There are two real solutions. Enter the lesser number first. Leave the answers in simplest fraction form.

Answer 3

To solve the equation \( x^2 = \frac{16}{25} \) by inspection, we need to find the numbers \( x \) such that when squared, they equal \( \frac{16}{25} \).

Taking the square root of both sides, we find:

\[ x = \pm \sqrt{\frac{16}{25}} \]

Calculating the square root:

\[ \sqrt{\frac{16}{25}} = \frac{\sqrt{16}}{\sqrt{25}} = \frac{4}{5} \]

This gives us the solutions:

\[ x = \frac{4}{5} \quad \text{and} \quad x = -\frac{4}{5} \]

Thus, the two real solutions, with the lesser number first, are:

\[ -\frac{4}{5}, \frac{4}{5} \]