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Solve the following equations by inspection. There are two real solutions. Enter the lesser number first.

(1 point)
1) x2=36
The solutions are:
and

2) x2=81
The solutions are:
and

3) x2=4
The solutions are:
and

4) x2=49
The solutions are:
and

5) x2=25
The solutions are:
and

1 answer

To solve the equations \( x^2 = k \) where \( k \) is the constant, we can simply take the square root of \( k \) to find the solutions. The two real solutions for each equation will be \( \sqrt{k} \) and \( -\sqrt{k} \).

  1. \( x^2 = 36 \)
    The solutions are:
    -6
    and 6

  2. \( x^2 = 81 \)
    The solutions are:
    -9
    and 9

  3. \( x^2 = 4 \)
    The solutions are:
    -2
    and 2

  4. \( x^2 = 49 \)
    The solutions are:
    -7
    and 7

  5. \( x^2 = 25 \)
    The solutions are:
    -5
    and 5

Thus, the final answers to enter for each equation are:

  1. -6 and 6
  2. -9 and 9
  3. -2 and 2
  4. -7 and 7
  5. -5 and 5