For quadratic equation :
a x ^ 2 + b x + c = 0
The solutions are:
x1/2 = [ - b + OR - sqroot ( b ^ 2 - 4 a c ) ] / 2 a
Int this case :
a = 1
b = 4
c = 6
x1/2 = [ - 4 + OR - sqroot ( 4 ^ 2 - 4 * 1 * 6 ) ] / ( 2 * 1 )
x1/2 = [ - 4 + OR - sqroot ( 16 - 24 ) ] / 2
x1/2 = [ - 4 + OR - sqroot ( - 8 ) ] / 2
x1/2 = [ - 4 + OR - sqroot ( - 1 * 4 * 2 ) ] / 2
x1/2 = [ - 4 + OR - sqroot ( - 1 ) * sqroot ( 4 ) * sqroot ( 2 ) ] / 2
x1/2 = [ - 4 + OR - i * 2 * sqroot ( 2 ) ] / 2
x1/2 = [ - 4 + OR - 2 i * sqroot ( 2 ) ] / 2
x1/2 = - 4 / 2 + OR - [ 2 i * sqroot ( 2 ) ] / 2
x1/2 = - 2 + OR - i * sqroot ( 2 )
The solutions are:
x = - 2 - i * sqroot ( 2 )
and
x = - 2 + i * sqroot ( 2 )
Solve using the Quadratic Formula (Find all complex-number solutions.) x2 + 4x + 6 = 0
I do not get this at all and this is just practice exercise. Please help as I have a test next week and if I do not get at least a C, I will not graduate. Thank you Thank you!!
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