Asked by Taina
15t^2+7t=2
The quadratic formula tells you that the solutions are:
t = [-b +/-sqrt (b^2 - 4ac]/ (2a)
In this case, a = 15, b = 7 and c = -2
solve the equation for t. What values for t will you get when you substitute the values you listed for a, b, and c in the quadratic formula?
The quadratic formula tells you that the solutions are:
t = [-b +/-sqrt (b^2 - 4ac]/ (2a)
In this case, a = 15, b = 7 and c = -2
solve the equation for t. What values for t will you get when you substitute the values you listed for a, b, and c in the quadratic formula?
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