Asked by sarah
solve using matricies
x+2y+3z=7
-x+2y-z=1
-x+y-2z=-2
x= y= z=
ive tried everyway I can think of please help
x+2y+3z=7
-x+2y-z=1
-x+y-2z=-2
x= y= z=
ive tried everyway I can think of please help
Answers
Answered by
Steve
one way:
Ax=B, so you want A^-1 so that
x = A^-1 B
A =
(1 2 3)
(-1 2 -1)
(-1 1 -2)
B =
(7)
(1)
(-2)
A^-1 = 1/2 *
(3 -7 8)
(1 -1 2)
(-1 3 -4)
Now if you supply the missing value in B, you can do the multiply and get (-1 1 2), the solution.
http://www.wolframalpha.com/input/?i=inverse+{{1,+2,+3},{-1,+2,+-1},{-1,+1,+-2}}+*+{{7},{1},{-2}}
Or, you can do row operations as in Gaussian elimination. There's a handy calculator at
http://www.gregthatcher.com/Mathematics/GaussJordan.aspx
Ax=B, so you want A^-1 so that
x = A^-1 B
A =
(1 2 3)
(-1 2 -1)
(-1 1 -2)
B =
(7)
(1)
(-2)
A^-1 = 1/2 *
(3 -7 8)
(1 -1 2)
(-1 3 -4)
Now if you supply the missing value in B, you can do the multiply and get (-1 1 2), the solution.
http://www.wolframalpha.com/input/?i=inverse+{{1,+2,+3},{-1,+2,+-1},{-1,+1,+-2}}+*+{{7},{1},{-2}}
Or, you can do row operations as in Gaussian elimination. There's a handy calculator at
http://www.gregthatcher.com/Mathematics/GaussJordan.aspx
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