SO
A=63
a=17
B=?
b=18
C=?
c=?
using law of sines
sine 63/17=sinB/18
SinB= sin63x18/17
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B=70.6 degrees '
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to find C
C= 180-63-70.6
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C= 46.4 degrees '
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using law of cosines
c^2=17^2+18^2-2(17)(18)(cos(46.4))
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c=13.8 '
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solve traingle ABC if A=63 degrees 10minutes, b=18 and a=17. Mark all solutions clearly.
2 answers
You ignored the 10 minutes of the 63º angle
so A = 63.1667º which would slightly alter your angles.
However I tested your solution for the angles if A = 63 and the angles are correct for that version
your value of c is correct for A=63
why did you use the cosine law?
The Sine Law would have been easier.
so A = 63.1667º which would slightly alter your angles.
However I tested your solution for the angles if A = 63 and the angles are correct for that version
your value of c is correct for A=63
why did you use the cosine law?
The Sine Law would have been easier.
1 answer