Asked by anon
Solve the triangle α = 27 degrees 30', c = 52.8, a = 28.1
Answers
Answered by
Steve
sinC/c = sinA/a, so
sinC/52.8 = sin27°30'/28.1
sinC = 0.8676
C = 60°11' or 119°49'
Since A+C < 180 in either case, there are two possible triangles.
Knowing A and C, you now know what B can be, and then use the law of sines again to find b.
sinC/52.8 = sin27°30'/28.1
sinC = 0.8676
C = 60°11' or 119°49'
Since A+C < 180 in either case, there are two possible triangles.
Knowing A and C, you now know what B can be, and then use the law of sines again to find b.
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