Solve the system of two equations using substitution.y=2+3x4x−3y=−16(1 point)Responses(2, 8)left parenthesis 2 comma 8 right parenthesis(2, 10) left parenthesis 2 comma 10 right parenthesis(−2, 4) left parenthesis negative 2 comma 4 right parenthesis(−2, −4)

Answer 1

To solve the system of equations using substitution, we first need to solve for one of the variables in one of the equations and then substitute that expression back into the other equation.

Given equations:
1. y = 2 + 3x
2. 4x - 3y = -16

From equation 1, we have y = 2 + 3x. We can then substitute this into equation 2:
4x - 3(2 + 3x) = -16
4x - 6 - 9x = -16
-5x = -10
x = 2

Now that we have found x = 2, we can substitute this back into y = 2 + 3x:
y = 2 + 3(2)
y = 2 + 6
y = 8

Therefore, the solution to the system of equations is (2, 8).