Solve the system of two equations using elimination with multiplication.

Question

4x - 6y=-48
-2x + 4y = 30 (1 point)
• (-21, -6)
• (-33, -9)
• (-3, 6)
• (3, 9)

Answer 1

First, stack the equations on top of each other:

4x - 6y = -48
-2x + 4y = 30

Next, multiply the second equation by 2 to make the coefficients of x the same but different in sign:

4x - 6y = -48
-4x + 8y = 60

Now, add the two equations together to eliminate x:

(4x - 6y) + (-4x + 8y) = -48 + 60
2y = 12
y = 6

Now substitute y=6 back into either equation to solve for x:

4x - 6(6) = -48
4x - 36 = -48
4x = -12
x = -3

So, the solution to the system of equations is (-3, 6), which means none of the provided options are correct.

Answer 2

please check your answer

Answer 3

Apologies for the error in my previous response. Let's re-solve the system of equations using elimination with multiplication:

4x - 6y = -48
-2x + 4y = 30

Let's multiply the first equation by 2 and the second equation by 3 to make the coefficients of x the same but different in sign:

8x - 12y = -96 (equation 1)
-6x + 12y = 90 (equation 2)

Now, add the two equations together to eliminate y:

(8x - 12y) + (-6x + 12y) = -96 + 90
2x = -6
x = -3

Substitute x = -3 back into the first equation:

4(-3) - 6y = -48
-12 - 6y = -48
-6y = -36
y = 6

Therefore, the correct solution to the system of equations is (-3, 6). So, the answer is (-3, 6).