To solve the system of equations using elimination with multiplication, we must first choose a variable to eliminate. In this case, we can eliminate the variable "x" by multiplying the first equation by 2 and the second equation by 4.
By multiplying the first equation by 2, we get 8x - 12y = -96.
By multiplying the second equation by 4, we get -8x + 16y = 120.
Now we can add these two equations together to eliminate the variable "x":
(8x - 12y) + (-8x + 16y) = (-96) + 120
-12y + 16y = 24
4y = 24
y = 6
Substitute the value of "y" = 6 back into either equation to find the value of "x". Let's use the first equation:
4x - 6(6) = -48
4x - 36 = -48
4x = -48 + 36
4x = -12
x = -12/4
x = -3
Therefore, the solution to the system of equations is (-3, 6).
Solve the system of two equations using elimination with multiplication. 4x−6y=−48 −2x+4y=30 (1 point) Responses (−21,−6) left parenthesis negative 21 comma negative 6 right parenthesis (−33,−9) left parenthesis negative 33 comma negative 9 right parenthesis (3, 9) left parenthesis 3 comma 9 right parenthesis (−3, 6)
1 answer